[OpenIndiana-discuss] RAIDZ performance
Reginald Beardsley
pulaskite at yahoo.com
Thu Feb 21 23:21:32 UTC 2013
Wow! I'm also deeply embarrassed for not having looked at the source myself before posting. I should have.
FWIW A 10x performance hit for double parity instead of single parity is probably a code tuning or algorithm issue.
Have Fun!
Reg
--- On Thu, 2/21/13, Sašo Kiselkov <skiselkov.ml at gmail.com> wrote:
> From: Sašo Kiselkov <skiselkov.ml at gmail.com>
> Subject: Re: [OpenIndiana-discuss] RAIDZ performance
> To: openindiana-discuss at openindiana.org
> Date: Thursday, February 21, 2013, 2:08 PM
> On 02/21/2013 07:27 PM, Timothy
> Coalson wrote:
> > I think last time this was asked, the consensus was
> that the implementation
> > was based on linear feedback shift registers and xor,
> which happens to be a
> > reed-solomon code (not as clear on this part, but what
> matters is what it
> > is, not what it isn't). Regardless, from reading
> the source previously, I
> > am fairly sure it operates bytewise, with xor for first
> syndrome (parity),
> > and LFSR and then xor for the other syndromes.
> >
> > See
> > http://openindiana.org/pipermail/openindiana-discuss/2012-October/010419.html
>
> I tore out the parity calculations for raidz1 and raidz2
> (attached) from
> vdev_raidz.c and here are the results:
>
> ("5 1 32 1000000" below means 1000000 iterations over a
> 5-drive
> raidz-1 at 32k per data drive; 4 data drives * 32k =
> 128k block)
> $ for ((I=0; $I < 2 ; I=$I + 1 )); do time ./raidz_test 5
> 1 32 1000000 &
> done
> real 0m32.045s
> user 0m32.336s
> sys 0m0.015s
>
> real 0m32.372s
> user 0m32.486s
> sys 0m0.017s
>
> So combined raidz1 throughput is:
> 128 * 1024 * 1000000 / 2^30 / 32 * 2 = 7.6293 GB/s
>
> ("4 2 64 1000000" below means 1000000 iterations over a
> 4-drive
> raidz-2 at 64k per data drive; 2 data drives * 64k =
> 128k block)
> RAIDZ2:
> for ((I=0; $I < 2 ; I=$I + 1 )); do time ./raidz_test 4 2
> 64 1000000 & done
> real 3m3.040s
> user 3m0.920s
> sys 0m0.078s
>
> real 3m3.082s
> user 3m1.092s
> sys 0m0.058s
>
> So combined raidz2 throughput is:
> 128 * 1024 * 1000000 / 2^30 / 183 * 2 = 1.3341 GB/s
>
> Next comes the factor of reduced data spindle count. A
> 4-drive raidz1
> will contain 3 data spindles, while a 4-drive raidz2 will
> only contain 2
> data spindles. Fewer spindles = less raw throughput.
>
> I think we can thus conclude that the performance drop
> Reginald is
> seeing is entirely expected.
>
> Cheers,
> --
> Saso
>
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>
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